Given a number N. The task is to write a program to find the Nth term of the below series:
0, 4, 14, 30, 51, 80, 114, 154, 200, …(N Terms)
Examples:
Input: N = 4
Output: 82
For N = 4
4th Term = ( 4 * 4 - 2 * 4 + 2)
= 10
Input: N = 10
Output: 122
Approach: The generalized Nth term of this series:
Below is the required implementation:
C++
// CPP program to find the N-th term of the series:// 5, 10, 17, 26, 37, 50, 65, 82, ...#include <iostream>#include <math.h>using namespace std;// calculate Nth term of seriesint nthTerm(int n){ return pow(n, 2) - 2 * n + 2;}// Driver Functionint main(){ int N = 4; cout << nthTerm(N); return 0;} |
Java
// Java program to find the N-th term of the series: // 5, 10, 17, 26, 37, 50, 65, 82, ... import java.util.*; class solution { // calculate Nth term of series static int nthTerm(int n) { //return the total sum return (int)Math.pow(n, 2) - 2 * n + 2; } //Driver function public static void main(String arr[]) { int N = 4; System.out.println(nthTerm(N)); } } |
Python3
# Python3 program to find the N-th # term of the series: # 0, 4, 14, 30, 51, 80, 114, 154, 200, …# from math lib. import everythingfrom math import *# calculate Nth term of series def nthTerm(n) : return pow(n, 2) - 2 * n + 2 # Driver code if __name__ == "__main__" : N = 4 print(nthTerm(N))# This code is contributed by # ANKITRAI1 |
C#
// C# program to find the // N-th term of the series: // 5, 10, 17, 26, 37, 50, 65, 82, ... using System;class GFG{// calculate Nth term of series public static int nthTerm(int n){ // return the total sum return (int)Math.Pow(n, 2) - 2 * n + 2;}// Driver Code public static void Main(string[] arr){ int N = 4; Console.WriteLine(nthTerm(N));}}// This code is contributed// by Shrikant13 |
PHP
<?php // PHP program to find the// N-th term of the series:// 5, 10, 17, 26, 37, 50, 65, 82, ...// calculate Nth term of seriesfunction nthTerm($n){ return pow($n, 2) - 2 * $n + 2;}// Driver Code$N = 4;echo nthTerm($N);// This code is contributed // by ChitraNayal?> |
Javascript
<script>// JavaScript program to find the N-th term of the series:// 5, 10, 17, 26, 37, 50, 65, 82, ...// calculate Nth term of seriesfunction nthTerm( n){ return Math.pow(n, 2) - 2 * n + 2;}// Driver code let N = 4; document.write( nthTerm(N) );// This code contributed by aashish1995 </script> |
Output:
10
Time Complexity: O(1), since there is no loop or recursion.
Space Complexity: O(1) since using constant variables
Feeling lost in the world of random DSA topics, wasting time without progress? It’s time for a change! Join our DSA course, where we’ll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 neveropen!
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 neveropen!
