In this article, we will discuss how to check if two numbers have the same last digit in JavaScript. Checking the last digit of a number is a common requirement in programming tasks, and it can be useful in various scenarios. We will explore an approach using JavaScript to accomplish this task.
Methods to Check Both Numbers have the Same Last Digit
- Using the Modulus Operator (%)
- Converting Numbers to Strings using
toString()Method - Using the Array of Digits using the Spread Operator
- Using the Bitwise AND Operator
We will explore every approach for checking if the Numbers Have the Same Last Digit, along with understanding their basic implementations.
Approach 1: Using the Modulus Operator (%)
- Take the modulus (%) of both numbers with 10 to extract their last digits.
- Compare the last digits using the ===.
- Return
trueif the last digits are the same, otherwise returnfalse.
Example:
Javascript
// Define function to check last digit of number function haveSameLastDigit(num1, num2) { // Getting last digit using % operator const lastDigit1 = num1 % 10; const lastDigit2 = num2 % 10; // Return if last digits are same or not return lastDigit1 === lastDigit2; } const number1 = 123; const number2 = 456; // Calling function with arguements const result = haveSameLastDigit(number1, number2); // Giving output console.log(result); |
Output
false
Approach 2: Converting Numbers to Strings
- Convert both numbers to strings using the
toString()method. - Get the last character (digit) of each string using the
slice()method. - Compare the last digits using the ===.
- Return
trueif the last digits are the same, otherwise returnfalse.
Syntax:
string.slice(startIndex, endIndex);
Example:
Javascript
// Define function to check last digit of number function haveSameLastDigit(num1, num2) { // Getting last digit using % operator const lastDigit1 = num1.toString().slice(-1); const lastDigit2 = num2.toString().slice(-1); // Return if last digits are same or not return lastDigit1 === lastDigit2; } const number1 = 123; const number2 = 453; // Calling function with arguements const result = haveSameLastDigit(number1, number2); // Giving output console.log(result); |
Output
true
Approach 3: Using the Array of Digits
- Create an array of digits for each number using the spread operator.
- Get the last digit of each array using the array index.
- Compare the last digits using the ===.
- Return
trueif the last digits are the same, otherwise returnfalse.
Syntax:
// Spread operator
[...iterable]
Example:
Javascript
// Define function to check last digit of number function haveSameLastDigit(num1, num2) { // Converting number to string const digits1 = [...num1.toString()]; const digits2 = [...num2.toString()]; // Getting last character of string const lastDigit1 = digits1[digits1.length - 1]; const lastDigit2 = digits2[digits2.length - 1]; // Return if last digits are same or not return lastDigit1 === lastDigit2; } const number1 = 123; const number2 = 453; // Calling function with arguements const result = haveSameLastDigit(number1, number2); // Giving output console.log(result); |
Output
true
Approach 4: Using the Bitwise AND Operator
- The Bitwise AND operator
&to perform a bitwise AND operation between the numbers and 1 (num1 & 1andnum2 & 1). - The result will be 1 if the last bit (last digit) of both numbers is the same, and 0 otherwise.
- Then, we compare the results using the strict equality operator
===to check if they are equal. - If they are equal, it means the numbers have the same last digit.
Syntax:
firstNum=num&1
Javascript
function hasSameLastDigit(num1, num2) { // Get the last bit of num1 const lastDigit1 = num1 & 1; // Get the last bit of num2 const lastDigit2 = num2 & 1; return lastDigit1 === lastDigit2; } // Example usage: const number1 = 123; const number2 = 453; const result = hasSameLastDigit(number1, number2); console.log(result); // Output: false |
Output
true
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